Re: Userform Login Attempt Counter, Close after 3 tries

Quote from KjBox;703418

OK here it is back (but not wrong now! )

You need to store the number of attempts in something other than a variable. The easiest way to do that is have another textbox on the form with visibility property set to False and a value of 2

Then refer to that textbox value rather than a variable (the value reduces by 1 after each failed attempt at logging in).

Code

Private Sub CommandButton1_Click()
    Dim sUserid, sPassword, sSearchID As String
    Dim rIdPwd As Range
    
    sUserid = Useridtextbox
    sPassword = Passwordtextbox
    sSearchID = sUserid & " " & sPassword
    Label1.Visible = False
    Label2.Visible = False
    
    If sUserid = vbNullString Then
        Label1.Visible = True: Exit Sub
    ElseIf sPassword = vbNullString Then
        Label2.Visible = True: Exit Sub
    End If
    
    With Sheets("User Master File Records").Range("a:a")
        Set rIdPwd = .Find(What:=sSearchID, LookIn:=xlValues, lookat:=xlWhole)
    End With
    
    If Not rIdPwd Is Nothing Then
        MsgBox "access granted"
        
        'Your code here to do whatever if access granted
        
        Unload Me
    Else
        MsgBox "Access denied, You have " & tbCnt & " attempt(s) left until the system closes"
        Useridtextbox = vbNullString
        Passwordtextbox = vbNullString
        tbCnt = tbCnt - 1
    End If
    If tbCnt = -1 Then
        MsgBox "bye"
        
        'Your code here to do whatever if access denied
        
        Unload Me
    End If
End Sub

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I am attaching a working sample.

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Good Day Sir/Maam,specially to Sir KJBOX,

Can i ask if how i know the Username and Password of this code?
If there is no declared user and pass here,then how to put user and pass in this code?