Can anyone experts can provides me the code to open a file in a folder(lot number) from the directory(local disk C) using one command button and 2 textboxs?Below is the illustaration what i'm going to do..
1. User enter directory and specify lot number(textbox). Then click Start button(command button).
[Blocked Image: http://i110.photobucket.com/albums/n81/poex_xp/project2.jpg]
In the lot number folder have the file which need to be open.
2. After Start button is clicked the file is open.
Please anyone help me. Thanks