What kind of help did you need?
There are tons of posts in many forums about populating cell comments and loops you must have tried something if you searched through many forums.
What kind of help did you need?
There are tons of posts in many forums about populating cell comments and loops you must have tried something if you searched through many forums.
.Offset(, 5)
Means 5 columns from column Q.
Select Q1 and hit the right arrow 5 times to V1
Using column Q to indicate the non blank cells, you can loop through column V to find values.
Sub GetData()
Dim rng As Range, c As Range, LstRw As Long
Set rng = Range("Q40:Q430").SpecialCells(xlCellTypeConstants, 23).Offset(, 5)
Application.EnableEvents = False
For Each c In rng.Cells
If c <> "" Then
LstRw = Cells(Rows.Count, "C").End(xlUp).Row + 1
Cells(LstRw, "C") = c
Cells(LstRw, "F") = c.Offset(, 3)
Cells(LstRw, "K") = c.Offset(, 8)
Cells(LstRw, "M") = c.Offset(, 10).Value
End If
Next
Application.EnableEvents = True
End Sub
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MyRng.EntireRow.Copy _
wbTo.Range("D" & lDestLastRow)
You can't copy an entire row to column D as that would make the data go outside the worksheet.
Edit: Ha, guess this was already said
You can also create an variable for the results of TextBox1 & TextBox2, set the variable to zero if the textbox is blank.
Private Sub TextBox1_Change()
Dim x
x = IIf(Me.TextBox2 = "", 0, Me.TextBox2)
TextBox3.Value = 250 - (TextBox1.Value - x)
End Sub
Private Sub TextBox2_Change()
Dim x, y
x = IIf(Me.TextBox2 = "", 0, Me.TextBox2)
y = IIf(Me.TextBox1 = "", 0, Me.TextBox1)
TextBox3.Value = 250 - (y - x)
End Sub
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cells E69:F69 need to be merged.
Both have different data but they both are on the same row.
You can have both column A & B in the same listbox, in your properties, change to column count=2 and change the range to include A2:B4
Here is the code, it just needs to be in the Command Button
Private Sub CommandButton1_Click()
Dim LstRw As Long
For x = 0 To ListBox1.ListCount - 1
If ListBox1.Selected(x) = True Then
With Sheet2
.Cells(.Rows.Count, 1).End(xlUp).Offset(1) = ListBox1.List(x, 0)
.Cells(.Rows.Count, 2).End(xlUp).Offset(1) = ListBox1.List(x, 1)
End With
End If
Next x
Unload Me
End Sub
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Try this.
Private Sub ListBox1_Change()
Dim LstRow As Long
UserForm1.ListBox2.Clear
UserForm1.ListBox2.AddItem Sheets("Sheet1").Cells(ListBox1.ListIndex + 2, 2)
With Sheet2
LstRow = .Cells(.Rows.Count, "A").End(xlUp).Row + 1
.Cells(LstRow, 1) = Me.ListBox1
.Cells(LstRow, 2) = Sheets("Sheet1").Cells(ListBox1.ListIndex + 2, 2)
End With
End Sub
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The" exit for" is the line the exits the loop after the first occurrence.
The code does not open the workbook, that error should not occur.
If you are attempting to open the workbook in the code, search for "Open workbook if not already open"
I have a code that copies and pastes a rang to outlook, I thought I would try using the print screen and pasting into outlook and it seems to do it.
See how it works for you.
Private Sub CommandButton1_Click()
Dim doc As Object, rng As Range
Application.SendKeys "(%{1068})"
DoEvents
'ActiveSheet.Paste
With CreateObject("Outlook.Application").CreateItem(0)
.display
Set doc = .GetInspector.WordEditor
doc.Range(0, 0).Paste
.To = "[email protected]"
.Subject = "Send Email Body"
End With
End Sub
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Give this a try,
Private Sub CommandButton1_Click()
Dim wb As Workbook
Dim sh As Worksheet, c As Range
Dim rng As Range
Set wb = Workbooks("Destination.xlsx")
Set sh = wb.Sheets("Sheet2")
With sh
Set rng = .Range("B2:B" & .Cells(.Rows.Count, "B").End(xlUp).Row)
For Each c In rng.Cells
If UCase(c) = UCase(Me.Range("D5").Value) Then
If UCase(c.Offset(, 3)) = UCase(Me.Range("D7")) Then
If c.Offset(, 4) = Me.Range("D8") Then
c.Offset(, 9) = "Calibration done"
Exit For
End If
End If
End If
Next c
End With
End Sub
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If you have a PDF printer you can print the userform
I removed most of the information in the database due to confidentiality reason as it is work involved
Your workbooks should show the original layout and what the required results should be.
Fill the sheets with phony data.
Supplying blank workbooks is not helpful
Hello,
What is the code doing and is it running slow?
Supply a sample workbook to go with the code so somebody can test it.
You need to remove .select
I don't get that result, but if you are getting 1 more than you want, you can always subtract 1 from `num`, you will have to make sure x does not equal zero though . Probably changing
if num>1
You don't want
for x=1 to 0